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10/2v=-5v-50
We move all terms to the left:
10/2v-(-5v-50)=0
Domain of the equation: 2v!=0We get rid of parentheses
v!=0/2
v!=0
v∈R
10/2v+5v+50=0
We multiply all the terms by the denominator
5v*2v+50*2v+10=0
Wy multiply elements
10v^2+100v+10=0
a = 10; b = 100; c = +10;
Δ = b2-4ac
Δ = 1002-4·10·10
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-40\sqrt{6}}{2*10}=\frac{-100-40\sqrt{6}}{20} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+40\sqrt{6}}{2*10}=\frac{-100+40\sqrt{6}}{20} $
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