10/3-40a/3=-7a/3+4/3(-3a-2)

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Solution for 10/3-40a/3=-7a/3+4/3(-3a-2) equation: 


a in (-oo:+oo)

10/3-((40*a)/3) = (4/3)*(-3*a-2)+(-7*a)/3 // - (4/3)*(-3*a-2)+(-7*a)/3

10/3-((4/3)*(-3*a-2))-((40*a)/3)-((-7*a)/3) = 0

(-4/3)*(-3*a-2)+(-40/3)*a+(7/3)*a+10/3 = 0

(-40*a)/3-4/3*(-3*a-2)+(7*a)/3+10/3 = 0

(-4/3*3*(-3*a-2))/3+(-40*a)/3+(7*a)/3+10/3 = 0

7*a-4/3*3*(-3*a-2)-40*a+10 = 0

7*a-28*a+8+10 = 0

8-21*a+10 = 0

18-21*a = 0

(18-21*a)/3 = 0

(18-21*a)/3 = 0 // * 3

18-21*a = 0

18-21*a = 0 // - 18

-21*a = -18 // : -21

a = -18/(-21)

a = 6/7

a = 6/7

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