10/35=4/n

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Solution for 10/35=4/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

10/35 = 4/n // - 4/n

10/35-(4/n) = 0

10/35-4*n^-1 = 0

-4*n^-1 = -2/7 // : -4

n^-1 = 1/14

-1 < 0

1/(n^1) = 1/14 // * n^1

1 = 1/14*n^1 // : 1/14

14 = n^1

n = 14

n = 14

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