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10/3a+5=3/a+1
We move all terms to the left:
10/3a+5-(3/a+1)=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: a+1)!=0We get rid of parentheses
a∈R
10/3a-3/a-1+5=0
We calculate fractions
10a/3a^2+(-9a)/3a^2-1+5=0
We add all the numbers together, and all the variables
10a/3a^2+(-9a)/3a^2+4=0
We multiply all the terms by the denominator
10a+(-9a)+4*3a^2=0
Wy multiply elements
12a^2+10a+(-9a)=0
We get rid of parentheses
12a^2+10a-9a=0
We add all the numbers together, and all the variables
12a^2+a=0
a = 12; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*12}=\frac{-2}{24} =-1/12 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*12}=\frac{0}{24} =0 $
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