10/3b=40

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Solution for 10/3b=40 equation: 



10/3b=40

We move all terms to the left:

10/3b-(40)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We multiply all the terms by the denominator


-40*3b+10=0

Wy multiply elements

-120b+10=0

We move all terms containing b to the left, all other terms to the right

-120b=-10

b=-10/-120

b=1/12

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