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10/3m+4/m=4
We move all terms to the left:
10/3m+4/m-(4)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: m!=0We calculate fractions
m∈R
10m/3m^2+12m/3m^2-4=0
We multiply all the terms by the denominator
10m+12m-4*3m^2=0
We add all the numbers together, and all the variables
22m-4*3m^2=0
Wy multiply elements
-12m^2+22m=0
a = -12; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-12)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-12}=\frac{-44}{-24} =1+5/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-12}=\frac{0}{-24} =0 $
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