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10/3x+3+4=-1-4(x+3)
We move all terms to the left:
10/3x+3+4-(-1-4(x+3))=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
10/3x-(-1-4(x+3))+7=0
We multiply all the terms by the denominator
-((-1-4(x+3)))*3x+7*3x+10=0
Wy multiply elements
-((-1-4(x+3)))*3x+21x+10=0
We add all the numbers together, and all the variables
21x-((-1-4(x+3)))*3x+10=0
We move all terms containing x to the left, all other terms to the right
21x-((-1-4(x+3)))*3x=-10
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