10/5h-2h=

Solution for 10/5h-2h= equation:

10/5h-2h=

We move all terms to the left:

10/5h-2h-()=0


Domain of the equation: 5h!=0

h!=0/5

h!=0

h∈R


We add all the numbers together, and all the variables

-2h+10/5h=0

We multiply all the terms by the denominator


-2h*5h+10=0

Wy multiply elements

-10h^2+10=0

a = -10; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-10)·10
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-10}=\frac{-20}{-20}
=1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-10}=\frac{20}{-20}
=-1
$