10/5x+10=35

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Solution for 10/5x+10=35 equation: 



10/5x+10=35

We move all terms to the left:

10/5x+10-(35)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

10/5x-25=0

We multiply all the terms by the denominator


-25*5x+10=0

Wy multiply elements

-125x+10=0

We move all terms containing x to the left, all other terms to the right

-125x=-10

x=-10/-125

x=2/25

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