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10/6x=x+4
We move all terms to the left:
10/6x-(x+4)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
10/6x-x-4=0
We multiply all the terms by the denominator
-x*6x-4*6x+10=0
Wy multiply elements
-6x^2-24x+10=0
a = -6; b = -24; c = +10;
Δ = b2-4ac
Δ = -242-4·(-6)·10
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{51}}{2*-6}=\frac{24-4\sqrt{51}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{51}}{2*-6}=\frac{24+4\sqrt{51}}{-12} $
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