10/7y-3/70=5/2y

Solution for 10/7y-3/70=5/2y equation:

10/7y-3/70=5/2y

We move all terms to the left:

10/7y-3/70-(5/2y)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

10/7y-(+5/2y)-3/70=0

We get rid of parentheses

10/7y-5/2y-3/70=0

We calculate fractions


(-84y^2)/6860y^2+9800y/6860y^2+(-17150y)/6860y^2=0

We multiply all the terms by the denominator


(-84y^2)+9800y+(-17150y)=0

We get rid of parentheses

-84y^2+9800y-17150y=0

We add all the numbers together, and all the variables

-84y^2-7350y=0

a = -84; b = -7350; c = 0;
Δ = b2-4ac
Δ = -73502-4·(-84)·0
Δ = 54022500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{54022500}=7350$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7350)-7350}{2*-84}=\frac{0}{-168}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7350)+7350}{2*-84}=\frac{14700}{-168}
=-87+1/2
$