10/j=35

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Solution for 10/j=35 equation: 



10/j=35

We move all terms to the left:

10/j-(35)=0



Domain of the equation: j!=0

j∈R



We multiply all the terms by the denominator


-35*j+10=0

We add all the numbers together, and all the variables

-35j+10=0

We move all terms containing j to the left, all other terms to the right

-35j=-10

j=-10/-35

j=2/7

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