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10/x+2=30/2x
We move all terms to the left:
10/x+2-(30/2x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10/x-(+30/2x)+2=0
We get rid of parentheses
10/x-30/2x+2=0
We calculate fractions
20x/2x^2+(-30x)/2x^2+2=0
We multiply all the terms by the denominator
20x+(-30x)+2*2x^2=0
Wy multiply elements
4x^2+20x+(-30x)=0
We get rid of parentheses
4x^2+20x-30x=0
We add all the numbers together, and all the variables
4x^2-10x=0
a = 4; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·4·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*4}=\frac{0}{8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*4}=\frac{20}{8} =2+1/2 $
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