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10/x+8=14/2x-5
We move all terms to the left:
10/x+8-(14/2x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-5)!=0We get rid of parentheses
x∈R
10/x-14/2x+5+8=0
We calculate fractions
20x/2x^2+(-14x)/2x^2+5+8=0
We add all the numbers together, and all the variables
20x/2x^2+(-14x)/2x^2+13=0
We multiply all the terms by the denominator
20x+(-14x)+13*2x^2=0
Wy multiply elements
26x^2+20x+(-14x)=0
We get rid of parentheses
26x^2+20x-14x=0
We add all the numbers together, and all the variables
26x^2+6x=0
a = 26; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·26·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*26}=\frac{-12}{52} =-3/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*26}=\frac{0}{52} =0 $
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