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10/x-28=2/3x
We move all terms to the left:
10/x-28-(2/3x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
10/x-(+2/3x)-28=0
We get rid of parentheses
10/x-2/3x-28=0
We calculate fractions
30x/3x^2+(-2x)/3x^2-28=0
We multiply all the terms by the denominator
30x+(-2x)-28*3x^2=0
Wy multiply elements
-84x^2+30x+(-2x)=0
We get rid of parentheses
-84x^2+30x-2x=0
We add all the numbers together, and all the variables
-84x^2+28x=0
a = -84; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-84)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-84}=\frac{-56}{-168} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-84}=\frac{0}{-168} =0 $
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