10/x=(1/2x)+38

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Solution for 10/x=(1/2x)+38 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x = (1/2)*x+38 // - (1/2)*x+38

10/x-((1/2)*x)-38 = 0

(-1/2)*x+10/x-38 = 0

10*x^-1-1/2*x^1-38*x^0 = 0

(10*x^0-1/2*x^2-38*x^1)/(x^1) = 0 // * x^2

x^1*(10*x^0-1/2*x^2-38*x^1) = 0

x^1

(-1/2)*x^2-38*x+10 = 0

(-1/2)*x^2-38*x+10 = 0

DELTA = (-38)^2-(4*10*(-1/2))

DELTA = 1464

DELTA > 0

x = (1464^(1/2)+38)/(2*(-1/2)) or x = (38-1464^(1/2))/(2*(-1/2))

x = -(2*366^(1/2)+38) or x = -(38-2*366^(1/2))

x in { -(2*366^(1/2)+38), -(38-2*366^(1/2))} 

x in { -(2*366^(1/2)+38), -(38-2*366^(1/2)) }

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