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10/x=11/3x+6.
We move all terms to the left:
10/x-(11/3x+6.)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+6.)!=0We add all the numbers together, and all the variables
x∈R
10/x-(11/3x+6)=0
We get rid of parentheses
10/x-11/3x-6=0
We calculate fractions
30x/3x^2+(-11x)/3x^2-6=0
We multiply all the terms by the denominator
30x+(-11x)-6*3x^2=0
Wy multiply elements
-18x^2+30x+(-11x)=0
We get rid of parentheses
-18x^2+30x-11x=0
We add all the numbers together, and all the variables
-18x^2+19x=0
a = -18; b = 19; c = 0;
Δ = b2-4ac
Δ = 192-4·(-18)·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-19}{2*-18}=\frac{-38}{-36} =1+1/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+19}{2*-18}=\frac{0}{-36} =0 $
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