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10/y+9=8y+6
We move all terms to the left:
10/y+9-(8y+6)=0
Domain of the equation: y!=0We get rid of parentheses
y∈R
10/y-8y-6+9=0
We multiply all the terms by the denominator
-8y*y-6*y+9*y+10=0
We add all the numbers together, and all the variables
3y-8y*y+10=0
Wy multiply elements
-8y^2+3y+10=0
a = -8; b = 3; c = +10;
Δ = b2-4ac
Δ = 32-4·(-8)·10
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{329}}{2*-8}=\frac{-3-\sqrt{329}}{-16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{329}}{2*-8}=\frac{-3+\sqrt{329}}{-16} $
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