100(1+x)+100(1+x)(1+x)+100(1+x)(1+x)(1+x)=0

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Solution for 100(1+x)+100(1+x)(1+x)+100(1+x)(1+x)(1+x)=0 equation: 



100(1+x)+100(1+x)(1+x)+100(1+x)(1+x)(1+x)=0

We add all the numbers together, and all the variables

100(x+1)+100(x+1)(x+1)+100(x+1)(x+1)(x+1)=0

We multiply parentheses

100x+100(x+1)(x+1)+100(x+1)(x+1)(x+1)+100=0

We multiply parentheses ..

100(+x^2+x+x+1)+100(+x^2+x+x+1)(x+1)+100x+100=0

We multiply parentheses

100x^2+100(+x^2+x+x+1)(x+1)+100x+100x+100x+100+100=0

We add all the numbers together, and all the variables

100x^2+100(+x^2+x+x+1)(x+1)+300x+200=0

We move all terms containing x to the left, all other terms to the right

100x^2+100(+x^2+x+x+1)(x+1)+300x=-200

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