100(35y-0.2)=100(15y+1)

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Solution for 100(35y-0.2)=100(15y+1) equation: 



100(35y-0.2)=100(15y+1)

We move all terms to the left:

100(35y-0.2)-(100(15y+1))=0

We multiply parentheses

3500y-(100(15y+1))-20=0



We calculate terms in parentheses: -(100(15y+1)), so:

100(15y+1)

We multiply parentheses

1500y+100

Back to the equation:

-(1500y+100)



We get rid of parentheses

3500y-1500y-100-20=0

We add all the numbers together, and all the variables

2000y-120=0

We move all terms containing y to the left, all other terms to the right

2000y=120

y=120/2000

y=3/50

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