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100-23x(x+8)=28
We move all terms to the left:
100-23x(x+8)-(28)=0
We add all the numbers together, and all the variables
-23x(x+8)+72=0
We multiply parentheses
-23x^2-184x+72=0
a = -23; b = -184; c = +72;
Δ = b2-4ac
Δ = -1842-4·(-23)·72
Δ = 40480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{40480}=\sqrt{16*2530}=\sqrt{16}*\sqrt{2530}=4\sqrt{2530}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-184)-4\sqrt{2530}}{2*-23}=\frac{184-4\sqrt{2530}}{-46} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-184)+4\sqrt{2530}}{2*-23}=\frac{184+4\sqrt{2530}}{-46} $
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