100-2x-5=(150-2x-2x)/1.10

Solution for 100-2x-5=(150-2x-2x)/1.10 equation:

100-2x-5=(150-2x-2x)/1.10

We move all terms to the left:

100-2x-5-((150-2x-2x)/1.10)=0

We add all the numbers together, and all the variables

-2x-((-4x+150)/1.10)+100-5=0

We add all the numbers together, and all the variables

-2x-((-4x+150)/1.10)+95=0

We multiply all the terms by the denominator


-2x*1.10)-((-4x+150)+95*1.10)=0

We add all the numbers together, and all the variables

-2x*1.10)-((-4x+150)=0

Wy multiply elements

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$