100-4u=(5u+6/4)+6

Solution for 100-4u=(5u+6/4)+6 equation:

100-4u=(5u+6/4)+6

We move all terms to the left:

100-4u-((5u+6/4)+6)=0

We add all the numbers together, and all the variables

-4u-((+5u+6/4)+6)+100=0

We multiply all the terms by the denominator


-4u*4)+6)-((+5u+6+100*4)+6)=0

We add all the numbers together, and all the variables

-4u*4)+6)-((5u+406)+6)=0

We add all the numbers together, and all the variables

-4u*4)+6)-((5u=0

Wy multiply elements

-16u^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{-32}=0$