100-4u=(5u+6/4)+6

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Solution for 100-4u=(5u+6/4)+6 equation:



100-4u=(5u+6/4)+6
We move all terms to the left:
100-4u-((5u+6/4)+6)=0
We add all the numbers together, and all the variables
-4u-((+5u+6/4)+6)+100=0
We multiply all the terms by the denominator
-4u*4)+6)-((+5u+6+100*4)+6)=0
We add all the numbers together, and all the variables
-4u*4)+6)-((5u+406)+6)=0
We add all the numbers together, and all the variables
-4u*4)+6)-((5u=0
Wy multiply elements
-16u^2=0
a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{-32}=0$

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