100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-33

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Solution for 100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-33 equation: 



100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-33

We move all terms to the left:

100-9(3x+15)-12(4x-9)+34-(150+2(x-3)-(4x-7)-33)=0

We add all the numbers together, and all the variables

-9(3x+15)-12(4x-9)-(150+2(x-3)-(4x-7)-33)+134=0

We multiply parentheses

-27x-48x-(150+2(x-3)-(4x-7)-33)-135+108+134=0



We calculate terms in parentheses: -(150+2(x-3)-(4x-7)-33), so:

150+2(x-3)-(4x-7)-33

determiningTheFunctionDomain
2(x-3)-(4x-7)+150-33

We add all the numbers together, and all the variables

2(x-3)-(4x-7)+117

We multiply parentheses

2x-(4x-7)-6+117

We get rid of parentheses

2x-4x+7-6+117

We add all the numbers together, and all the variables

-2x+118

Back to the equation:

-(-2x+118)



We add all the numbers together, and all the variables

-75x-(-2x+118)+107=0

We get rid of parentheses

-75x+2x-118+107=0

We add all the numbers together, and all the variables

-73x-11=0

We move all terms containing x to the left, all other terms to the right

-73x=11

x=11/-73

x=-11/73

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