100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-34

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Solution for 100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-34 equation: 



100-9(3x+15)-12(4x-9)+34=150+2(x-3)-(4x-7)-34

We move all terms to the left:

100-9(3x+15)-12(4x-9)+34-(150+2(x-3)-(4x-7)-34)=0

We add all the numbers together, and all the variables

-9(3x+15)-12(4x-9)-(150+2(x-3)-(4x-7)-34)+134=0

We multiply parentheses

-27x-48x-(150+2(x-3)-(4x-7)-34)-135+108+134=0



We calculate terms in parentheses: -(150+2(x-3)-(4x-7)-34), so:

150+2(x-3)-(4x-7)-34

determiningTheFunctionDomain
2(x-3)-(4x-7)+150-34

We add all the numbers together, and all the variables

2(x-3)-(4x-7)+116

We multiply parentheses

2x-(4x-7)-6+116

We get rid of parentheses

2x-4x+7-6+116

We add all the numbers together, and all the variables

-2x+117

Back to the equation:

-(-2x+117)



We add all the numbers together, and all the variables

-75x-(-2x+117)+107=0

We get rid of parentheses

-75x+2x-117+107=0

We add all the numbers together, and all the variables

-73x-10=0

We move all terms containing x to the left, all other terms to the right

-73x=10

x=10/-73

x=-10/73

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