1000(6x-10)=20(1,560+100x)

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Solution for 1000(6x-10)=20(1,560+100x) equation: 



1000(6x-10)=20(1.560+100x)

We move all terms to the left:

1000(6x-10)-(20(1.560+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(20(100x+1.56))=0

We multiply parentheses

6000x-(20(100x+1.56))-10000=0



We calculate terms in parentheses: -(20(100x+1.56)), so:

20(100x+1.56)

We multiply parentheses

2000x+31.2

Back to the equation:

-(2000x+31.2)



We get rid of parentheses

6000x-2000x-31.2-10000=0

We add all the numbers together, and all the variables

4000x-10031.2=0

We move all terms containing x to the left, all other terms to the right

4000x=10031.2

x=10031.2/4000

x=2+1692.66666667/3333.33333333

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