1000(6x-10)=20(1,680+100x)

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Solution for 1000(6x-10)=20(1,680+100x) equation:



1000(6x-10)=20(1.680+100x)
We move all terms to the left:
1000(6x-10)-(20(1.680+100x))=0
We add all the numbers together, and all the variables
1000(6x-10)-(20(100x+1.68))=0
We multiply parentheses
6000x-(20(100x+1.68))-10000=0
We calculate terms in parentheses: -(20(100x+1.68)), so:
20(100x+1.68)
We multiply parentheses
2000x+33.6
Back to the equation:
-(2000x+33.6)
We get rid of parentheses
6000x-2000x-33.6-10000=0
We add all the numbers together, and all the variables
4000x-10033.6=0
We move all terms containing x to the left, all other terms to the right
4000x=10033.6
x=10033.6/4000
x=2+1270.9999999997/2499.9999999994

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