1000(6x-10)=20(1,840+100x)

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Solution for 1000(6x-10)=20(1,840+100x) equation: 



1000(6x-10)=20(1.840+100x)

We move all terms to the left:

1000(6x-10)-(20(1.840+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(20(100x+1.84))=0

We multiply parentheses

6000x-(20(100x+1.84))-10000=0



We calculate terms in parentheses: -(20(100x+1.84)), so:

20(100x+1.84)

We multiply parentheses

2000x+36.8

Back to the equation:

-(2000x+36.8)



We get rid of parentheses

6000x-2000x-36.8-10000=0

We add all the numbers together, and all the variables

4000x-10036.8=0

We move all terms containing x to the left, all other terms to the right

4000x=10036.8

x=10036.8/4000

x=2+424.3333333334/833.33333333346

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