1000(6x-10)=20(1,880+100x)

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Solution for 1000(6x-10)=20(1,880+100x) equation: 



1000(6x-10)=20(1.880+100x)

We move all terms to the left:

1000(6x-10)-(20(1.880+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(20(100x+1.88))=0

We multiply parentheses

6000x-(20(100x+1.88))-10000=0



We calculate terms in parentheses: -(20(100x+1.88)), so:

20(100x+1.88)

We multiply parentheses

2000x+37.6

Back to the equation:

-(2000x+37.6)



We get rid of parentheses

6000x-2000x-37.6-10000=0

We add all the numbers together, and all the variables

4000x-10037.6=0

We move all terms containing x to the left, all other terms to the right

4000x=10037.6

x=10037.6/4000

x=2+1273.4999999997/2499.9999999994

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