1000(6x-10)=40(365+40x)

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Solution for 1000(6x-10)=40(365+40x) equation: 



1000(6x-10)=40(365+40x)

We move all terms to the left:

1000(6x-10)-(40(365+40x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(40x+365))=0

We multiply parentheses

6000x-(40(40x+365))-10000=0



We calculate terms in parentheses: -(40(40x+365)), so:

40(40x+365)

We multiply parentheses

1600x+14600

Back to the equation:

-(1600x+14600)



We get rid of parentheses

6000x-1600x-14600-10000=0

We add all the numbers together, and all the variables

4400x-24600=0

We move all terms containing x to the left, all other terms to the right

4400x=24600

x=24600/4400

x=5+13/22

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