1000(6x-10)=40(415+100x)

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Solution for 1000(6x-10)=40(415+100x) equation: 



1000(6x-10)=40(415+100x)

We move all terms to the left:

1000(6x-10)-(40(415+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(100x+415))=0

We multiply parentheses

6000x-(40(100x+415))-10000=0



We calculate terms in parentheses: -(40(100x+415)), so:

40(100x+415)

We multiply parentheses

4000x+16600

Back to the equation:

-(4000x+16600)



We get rid of parentheses

6000x-4000x-16600-10000=0

We add all the numbers together, and all the variables

2000x-26600=0

We move all terms containing x to the left, all other terms to the right

2000x=26600

x=26600/2000

x=13+3/10

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