1000(6x-10)=40(445+100x)

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Solution for 1000(6x-10)=40(445+100x) equation: 



1000(6x-10)=40(445+100x)

We move all terms to the left:

1000(6x-10)-(40(445+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(100x+445))=0

We multiply parentheses

6000x-(40(100x+445))-10000=0



We calculate terms in parentheses: -(40(100x+445)), so:

40(100x+445)

We multiply parentheses

4000x+17800

Back to the equation:

-(4000x+17800)



We get rid of parentheses

6000x-4000x-17800-10000=0

We add all the numbers together, and all the variables

2000x-27800=0

We move all terms containing x to the left, all other terms to the right

2000x=27800

x=27800/2000

x=13+9/10

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