1000(6x-10)=40(485+100x)

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Solution for 1000(6x-10)=40(485+100x) equation: 



1000(6x-10)=40(485+100x)

We move all terms to the left:

1000(6x-10)-(40(485+100x))=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(100x+485))=0

We multiply parentheses

6000x-(40(100x+485))-10000=0



We calculate terms in parentheses: -(40(100x+485)), so:

40(100x+485)

We multiply parentheses

4000x+19400

Back to the equation:

-(4000x+19400)



We get rid of parentheses

6000x-4000x-19400-10000=0

We add all the numbers together, and all the variables

2000x-29400=0

We move all terms containing x to the left, all other terms to the right

2000x=29400

x=29400/2000

x=14+7/10

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