1000(8x-10)=40(1120+100x)

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Solution for 1000(8x-10)=40(1120+100x) equation: 



1000(8x-10)=40(1120+100x)

We move all terms to the left:

1000(8x-10)-(40(1120+100x))=0

We add all the numbers together, and all the variables

1000(8x-10)-(40(100x+1120))=0

We multiply parentheses

8000x-(40(100x+1120))-10000=0



We calculate terms in parentheses: -(40(100x+1120)), so:

40(100x+1120)

We multiply parentheses

4000x+44800

Back to the equation:

-(4000x+44800)



We get rid of parentheses

8000x-4000x-44800-10000=0

We add all the numbers together, and all the variables

4000x-54800=0

We move all terms containing x to the left, all other terms to the right

4000x=54800

x=54800/4000

x=13+7/10

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