1000(9x-10)=50(688+10x)

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Solution for 1000(9x-10)=50(688+10x) equation: 



1000(9x-10)=50(688+10x)

We move all terms to the left:

1000(9x-10)-(50(688+10x))=0

We add all the numbers together, and all the variables

1000(9x-10)-(50(10x+688))=0

We multiply parentheses

9000x-(50(10x+688))-10000=0



We calculate terms in parentheses: -(50(10x+688)), so:

50(10x+688)

We multiply parentheses

500x+34400

Back to the equation:

-(500x+34400)



We get rid of parentheses

9000x-500x-34400-10000=0

We add all the numbers together, and all the variables

8500x-44400=0

We move all terms containing x to the left, all other terms to the right

8500x=44400

x=44400/8500

x=5+19/85

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