1000(9x-10)=50=(992+100x

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Solution for 1000(9x-10)=50=(992+100x equation: 



1000(9x-10)=50=(992+100x

We move all terms to the left:

1000(9x-10)-(50)=0

We multiply parentheses

9000x-10000-50=0

We add all the numbers together, and all the variables

9000x-10050=0

We move all terms containing x to the left, all other terms to the right

9000x=10050

x=10050/9000

x=1+7/60

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