1000(t)=-16(t)2+315t

Solution for 1000(t)=-16(t)2+315t equation:

1000(t)=-16(t)2+315t

We move all terms to the left:

1000(t)-(-16(t)2+315t)=0

We add all the numbers together, and all the variables

-(-16t^2+315t)+1000t=0

We get rid of parentheses

16t^2-315t+1000t=0

We add all the numbers together, and all the variables

16t^2+685t=0

a = 16; b = 685; c = 0;
Δ = b2-4ac
Δ = 6852-4·16·0
Δ = 469225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{469225}=685$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(685)-685}{2*16}=\frac{-1370}{32}
=-42+13/16
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(685)+685}{2*16}=\frac{0}{32}
=0
$