1000+24(n-12)=740+32(n-10)

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Solution for 1000+24(n-12)=740+32(n-10) equation: 



1000+24(n-12)=740+32(n-10)

We move all terms to the left:

1000+24(n-12)-(740+32(n-10))=0

We multiply parentheses

24n-(740+32(n-10))-288+1000=0



We calculate terms in parentheses: -(740+32(n-10)), so:

740+32(n-10)

determiningTheFunctionDomain
32(n-10)+740

We multiply parentheses

32n-320+740

We add all the numbers together, and all the variables

32n+420

Back to the equation:

-(32n+420)



We add all the numbers together, and all the variables

24n-(32n+420)+712=0

We get rid of parentheses

24n-32n-420+712=0

We add all the numbers together, and all the variables

-8n+292=0

We move all terms containing n to the left, all other terms to the right

-8n=-292

n=-292/-8

n=36+1/2

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