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1000n^2=2n
We move all terms to the left:
1000n^2-(2n)=0
a = 1000; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·1000·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*1000}=\frac{0}{2000} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*1000}=\frac{4}{2000} =1/500 $
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