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1000x^2-64=0
a = 1000; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·1000·(-64)
Δ = 256000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{256000}=\sqrt{25600*10}=\sqrt{25600}*\sqrt{10}=160\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160\sqrt{10}}{2*1000}=\frac{0-160\sqrt{10}}{2000} =-\frac{160\sqrt{10}}{2000} =-\frac{2\sqrt{10}}{25} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160\sqrt{10}}{2*1000}=\frac{0+160\sqrt{10}}{2000} =\frac{160\sqrt{10}}{2000} =\frac{2\sqrt{10}}{25} $
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