1008=(2x-4)(x+6)

Solution for 1008=(2x-4)(x+6) equation:

1008=(2x-4)(x+6)

We move all terms to the left:

1008-((2x-4)(x+6))=0

We multiply parentheses ..

-((+2x^2+12x-4x-24))+1008=0


We calculate terms in parentheses: -((+2x^2+12x-4x-24)), so:

(+2x^2+12x-4x-24)

We get rid of parentheses

2x^2+12x-4x-24

We add all the numbers together, and all the variables

2x^2+8x-24

Back to the equation:

-(2x^2+8x-24)


We get rid of parentheses

-2x^2-8x+24+1008=0

We add all the numbers together, and all the variables

-2x^2-8x+1032=0

a = -2; b = -8; c = +1032;
Δ = b2-4ac
Δ = -82-4·(-2)·1032
Δ = 8320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8320}=\sqrt{64*130}=\sqrt{64}*\sqrt{130}=8\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{130}}{2*-2}=\frac{8-8\sqrt{130}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{130}}{2*-2}=\frac{8+8\sqrt{130}}{-4}
$