100=(1-x)/(2+x)

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Solution for 100=(1-x)/(2+x) equation: 



100=(1-x)/(2+x)

We move all terms to the left:

100-((1-x)/(2+x))=0



Domain of the equation: (2+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

-((-1x+1)/(x+2))+100=0

We multiply all the terms by the denominator


-((-1x+1)+100*(x+2))=0



We calculate terms in parentheses: -((-1x+1)+100*(x+2)), so:

(-1x+1)+100*(x+2)

We multiply parentheses

(-1x+1)+100x+200

We get rid of parentheses

-1x+100x+1+200

We add all the numbers together, and all the variables

99x+201

Back to the equation:

-(99x+201)



We get rid of parentheses

-99x-201=0

We move all terms containing x to the left, all other terms to the right

-99x=201

x=201/-99

x=-2+1/33

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