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100=16x^2+36
We move all terms to the left:
100-(16x^2+36)=0
We get rid of parentheses
-16x^2-36+100=0
We add all the numbers together, and all the variables
-16x^2+64=0
a = -16; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-16)·64
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-16}=\frac{-64}{-32} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-16}=\frac{64}{-32} =-2 $
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