100=3/(.12-g)

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Solution for 100=3/(.12-g) equation: 



100=3/(.12-g)

We move all terms to the left:

100-(3/(.12-g))=0



Domain of the equation: (.12-g))!=0

We move all terms containing g to the left, all other terms to the right

-g)!=-.12

g!=-.12/1

g!=-.12

g∈R



We add all the numbers together, and all the variables

-(3/(-1g+0.12))+100=0

We multiply all the terms by the denominator


-(3+100*(-1g+0.12))=0



We calculate terms in parentheses: -(3+100*(-1g+0.12)), so:

3+100*(-1g+0.12)

determiningTheFunctionDomain
100*(-1g+0.12)+3

We multiply parentheses

-100g+12+3

We add all the numbers together, and all the variables

-100g+15

Back to the equation:

-(-100g+15)



We get rid of parentheses

100g-15=0

We move all terms containing g to the left, all other terms to the right

100g=15

g=15/100

g=3/20

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