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100=5x(x-1)
We move all terms to the left:
100-(5x(x-1))=0
We calculate terms in parentheses: -(5x(x-1)), so:We get rid of parentheses
5x(x-1)
We multiply parentheses
5x^2-5x
Back to the equation:
-(5x^2-5x)
-5x^2+5x+100=0
a = -5; b = 5; c = +100;
Δ = b2-4ac
Δ = 52-4·(-5)·100
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-45}{2*-5}=\frac{-50}{-10} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+45}{2*-5}=\frac{40}{-10} =-4 $
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