100=x2-12x+100

Solution for 100=x2-12x+100 equation:

100=x2-12x+100

We move all terms to the left:

100-(x2-12x+100)=0

We add all the numbers together, and all the variables

-(+x^2-12x+100)+100=0

We get rid of parentheses

-x^2+12x-100+100=0

We add all the numbers together, and all the variables

-1x^2+12x=0

a = -1; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-1)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-1}=\frac{-24}{-2}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-1}=\frac{0}{-2}
=0
$