100n2+900n-18800=0

Solution for 100n2+900n-18800=0 equation:

100n^2+900n-18800=0

a = 100; b = 900; c = -18800;
Δ = b2-4ac
Δ = 9002-4·100·(-18800)
Δ = 8330000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8330000}=\sqrt{490000*17}=\sqrt{490000}*\sqrt{17}=700\sqrt{17}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(900)-700\sqrt{17}}{2*100}=\frac{-900-700\sqrt{17}}{200}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(900)+700\sqrt{17}}{2*100}=\frac{-900+700\sqrt{17}}{200}
$