100x2+100x=2000

Solution for 100x2+100x=2000 equation:

100x^2+100x=2000

We move all terms to the left:

100x^2+100x-(2000)=0

a = 100; b = 100; c = -2000;
Δ = b2-4ac
Δ = 1002-4·100·(-2000)
Δ = 810000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{810000}=900$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-900}{2*100}=\frac{-1000}{200}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+900}{2*100}=\frac{800}{200}
=4
$