100z(z-0.2)=-10(5z+0.8)

Solution for 100z(z-0.2)=-10(5z+0.8) equation:

100z(z-0.2)=-10(5z+0.8)

We move all terms to the left:

100z(z-0.2)-(-10(5z+0.8))=0

We multiply parentheses

100z^2-20z-(-10(5z+0.8))=0


We calculate terms in parentheses: -(-10(5z+0.8)), so:

-10(5z+0.8)

We multiply parentheses

-50z-8

Back to the equation:

-(-50z-8)


We get rid of parentheses

100z^2-20z+50z+8=0

We add all the numbers together, and all the variables

100z^2+30z+8=0

a = 100; b = 30; c = +8;
Δ = b2-4ac
Δ = 302-4·100·8
Δ = -2300
Delta is less than zero, so there is no solution for the equation