101(1+3b)=-20

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Solution for 101(1+3b)=-20 equation: 



101(1+3b)=-20

We move all terms to the left:

101(1+3b)-(-20)=0

We add all the numbers together, and all the variables

101(3b+1)-(-20)=0

We add all the numbers together, and all the variables

101(3b+1)+20=0

We multiply parentheses

303b+101+20=0

We add all the numbers together, and all the variables

303b+121=0

We move all terms containing b to the left, all other terms to the right

303b=-121

b=-121/303

b=-121/303

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